gmatbull wrote:
What is the value of x?
(1) \(3x^2 + 8x + \frac{16}{3} = 0\)
(2) \(15x^2 + \frac{80}{3} = -40x\)
Target question: What is the value of x? Statement 1: 3x² + 8x + 16/3 = 0 Let's first eliminate the fractions by multiplying both sides of the equation by 3
When we do this, we get: 9x² + 24x + 16 = 0
Factor to get: (3x + 4)(3x + 4) = 0
So, it must be the case that 3x + 4 = 0
So, 3x = -4
x = -4/3
So,
the answer to the target question is x = -4/3Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: 15x² + 80/3 = -40xLet's first eliminate the fractions by multiplying both sides of the equation by 3
When we do this, we get: 45x² + 80 = -120x
Add 120x to both sides: 45x² + 120x + 80 =0
Divide both sides by 5 to get: When we do this, we get: 9x² + 24x + 16 = 0
This is the
same equation we had in statement 1
So,
the answer to the target question is x = -4/3Since we can answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: D
Cheers,
Brent
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